document.write( "Question 630604: $\"++%28log%28%28z%29%29%29%5E2=log%28%28z%5E2%29%29++\"$ \n" ); document.write( "

Algebra.Com's Answer #397038 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
(log(z))^2=log(z^2)
\n" ); document.write( "(log(z))^2-log(z^2)=0
\n" ); document.write( "(log(z))^2-2log(z)=0
\n" ); document.write( "log(z)(log(z)-2)=0
\n" ); document.write( "log(z)=0
\n" ); document.write( "z=1
\n" ); document.write( "or
\n" ); document.write( "log(z)-2=0
\n" ); document.write( "log(z)=2
\n" ); document.write( "z=100 \n" ); document.write( "

\n" );