document.write( "Question 630595: Need help on Log equation:
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Algebra.Com's Answer #397036 by stanbon(75887) ![]() You can put this solution on YOUR website! 4(1.02)^x=3(1.03)^x\r \n" ); document.write( "\n" ); document.write( "----------- \n" ); document.write( "(1.02/1.03)^x = 3/4 \n" ); document.write( "---- \n" ); document.write( "x*log[(1.02/1.03)] = log(3/4) \n" ); document.write( "---- \n" ); document.write( "x*(-0.0042) = -1.2493 \n" ); document.write( "x = 29.3872 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |