document.write( "Question 630595: Need help on Log equation:
\n" ); document.write( "\"+4%281.02%29%5Ex=3%281.03%29%5Ex+\"
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Algebra.Com's Answer #397036 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
4(1.02)^x=3(1.03)^x\r
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\n" ); document.write( "(1.02/1.03)^x = 3/4
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\n" ); document.write( "x*log[(1.02/1.03)] = log(3/4)
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\n" ); document.write( "x*(-0.0042) = -1.2493
\n" ); document.write( "x = 29.3872
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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