document.write( "Question 630591: I need help solving this Log equation
\n" ); document.write( "4(1.02)^x=3(1.0)^x
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Algebra.Com's Answer #397025 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
4(1.02)^x=3(1.0)^x=3 (1 raised to any number=1)
\n" ); document.write( "4(1.02)^x=3
\n" ); document.write( "(1.02)^x=3/4
\n" ); document.write( "xlog(1.02)=log3-log4
\n" ); document.write( "x=(log3-log4)/log(1.02)
\n" ); document.write( "x≈-14.5275
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