document.write( "Question 630587: SOS!\r
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document.write( "-5 <= 2x + 7 <= 3 \n" );
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Algebra.Com's Answer #397021 by lwsshak3(11628) ![]() You can put this solution on YOUR website! -5 <= 2x + 7 <= 3 \n" ); document.write( "-5 ≤ 2x+7 ≤ 3 \n" ); document.write( "add -7 \n" ); document.write( "-12 ≤ 2x ≤ -4 \n" ); document.write( "divide by 2 \n" ); document.write( "-6 ≤ x ≤ -2 \n" ); document.write( "number line: \n" ); document.write( "<....[-6<===>-2]........> \n" ); document.write( "solution: \n" ); document.write( "[-6,-2] \n" ); document.write( " |