document.write( "Question 630587: SOS!\r
\n" ); document.write( "\n" ); document.write( "-5 <= 2x + 7 <= 3
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Algebra.Com's Answer #397021 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
-5 <= 2x + 7 <= 3
\n" ); document.write( "-5 ≤ 2x+7 ≤ 3
\n" ); document.write( "add -7
\n" ); document.write( "-12 ≤ 2x ≤ -4
\n" ); document.write( "divide by 2
\n" ); document.write( "-6 ≤ x ≤ -2
\n" ); document.write( "number line:
\n" ); document.write( "<....[-6<===>-2]........>
\n" ); document.write( "solution:
\n" ); document.write( "[-6,-2]
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