document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630577>Question 630577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 2 ft less than the length.  The area is 24ft^2. Find the length and the width </SPAN>\n" );
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document.write( "W = L - 2\r<BR>\n" );
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document.write( "Area = 24 Ft^2\r<BR>\n" );
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document.write( "Equations: \r<BR>\n" );
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document.write( "a. Area of a rectangle = W * L\r<BR>\n" );
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document.write( "b. Quadratic equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "a. Area = W * L = (L-2) * L = 24 ---->  L^2 - 2L - 24 = 0\r<BR>\n" );
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document.write( "b. Quadratic equation: a = 1, b = -2, c = -24\r<BR>\n" );
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document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%2A%281%29%2A%28-24%29+%29%29%2F%282%2A%281%29%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "L = 1 +- 5 ---->  L = 6  or L = -4, Since this is a rectangle being constructed the measurement cannot be negative and so the only logical answer can be L = 6.\r<BR>\n" );
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document.write( "If we now substitute 6 into the width equation which was given we get W=4.\r<BR>\n" );
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document.write( "Now we can verify that the area is indeed 24 ft^2 = 6*4. </SPAN>\n" );
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