document.write( "Question 630356: If X is a normal random variable with standard deviation 3.50, and if the probability that X is more than 12.33 is .1271, then what is the mean of X? \n" ); document.write( "
Algebra.Com's Answer #397008 by stanbon(75887)\"\" \"About 
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If X is a normal random variable with standard deviation 3.50, and if the probability that X is more than 12.33 is .1271, then what is the mean of X?
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\n" ); document.write( "P(x > 12.33) = 0.1271
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\n" ); document.write( "Find the z-value with a right tail of 0.1271
\n" ); document.write( "invNorm(1-0.1271) = 1.1402
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\n" ); document.write( "Use z = (x-u)/s to find u.
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\n" ); document.write( "1.1402 = (12.33-u)/3.50
\n" ); document.write( "-u = (1.1402*3.50) - 12.33
\n" ); document.write( "-u = -8.3393
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\n" ); document.write( "u = 8.3393
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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