document.write( "Question 630356: If X is a normal random variable with standard deviation 3.50, and if the probability that X is more than 12.33 is .1271, then what is the mean of X? \n" ); document.write( "
Algebra.Com's Answer #397008 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If X is a normal random variable with standard deviation 3.50, and if the probability that X is more than 12.33 is .1271, then what is the mean of X? \n" ); document.write( "---- \n" ); document.write( "P(x > 12.33) = 0.1271 \n" ); document.write( "--- \n" ); document.write( "Find the z-value with a right tail of 0.1271 \n" ); document.write( "invNorm(1-0.1271) = 1.1402 \n" ); document.write( "--- \n" ); document.write( "Use z = (x-u)/s to find u. \n" ); document.write( "--- \n" ); document.write( "1.1402 = (12.33-u)/3.50 \n" ); document.write( "-u = (1.1402*3.50) - 12.33 \n" ); document.write( "-u = -8.3393 \n" ); document.write( "---- \n" ); document.write( "u = 8.3393 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |