document.write( "Question 630501: The perimeter of a semicircle is doubled when the radius is increased by 3. Find the radius of the semicircle. \n" ); document.write( "
Algebra.Com's Answer #396982 by nerdybill(7384)\"\" \"About 
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The perimeter of a semicircle is doubled when the radius is increased by 3. Find the radius of the semicircle.
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\n" ); document.write( "perimeter of semicircle:
\n" ); document.write( "(pi)d/2 + d
\n" ); document.write( "in terms of r:
\n" ); document.write( "(pi)r/4 + 2r
\n" ); document.write( "r(pi/4 + 2)
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\n" ); document.write( "From: \"perimeter of a semicircle is doubled when the radius is increased by 3\" we get our equation:
\n" ); document.write( "2(r(pi/4 + 2)) = (r+3)(pi/4 + 2)
\n" ); document.write( "2(r(pi/4 + 2)) = 2(r+3)(pi/8 + 1)
\n" ); document.write( "r(pi/4 + 2) = (r+3)(pi/8 + 1)
\n" ); document.write( "r*pi/4 + 2r = rpi/8 + r + 3pi/8 +3
\n" ); document.write( "r*pi/4 + 2r -rpi/8 - r = 3pi/8 +3
\n" ); document.write( "r(pi/4 + 2 -pi/8 - 1) = 3pi/8 +3
\n" ); document.write( "r(pi/4 - pi/8 + 1) = 3pi/8 +3
\n" ); document.write( "r(2pi/8 - pi/8 + 1) = 3pi/8 +3
\n" ); document.write( "r(pi/8 + 1) = 3pi/8 +3
\n" ); document.write( "r(pi/8 + 1) = 3(pi/8 +1)
\n" ); document.write( "r = 3\"\r
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