document.write( "Question 630434: you invest a total of 3000 in two accounts paying 3% and 6% interest, respectively at the end of the year, tha accounts earn the same amount of interest. how much was invested alt each rate? \n" ); document.write( "
Algebra.Com's Answer #396961 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "total of 3000 in two accounts paying 3% and 6% interest
\n" ); document.write( "at the end of the year, tha accounts earn the same amount of interest\r
\n" ); document.write( "\n" ); document.write( "Let x represent the amount earned at the larger rate:
\n" ); document.write( "Question states***
\n" ); document.write( " .06x = .03(3000-x) \r
\n" ); document.write( "\n" ); document.write( "how much was invested at each rate: solve for x and also determine (3000-x) \n" ); document.write( "
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