document.write( "Question 630464: X = - 1/4 y2 + y + 2\r
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\n" ); document.write( "\n" ); document.write( "a. Put this equation in standard form for a parabola.
\n" ); document.write( "b. What direction does it open in?
\n" ); document.write( "c. What is the coordinate of the vertex?
\n" ); document.write( "d. Sketch the graph of the parabola.
\n" ); document.write( "e. Find one point on your graph, and test it on the original equation.
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Algebra.Com's Answer #396936 by lwsshak3(11628)\"\" \"About 
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X = - 1/4 y2 + y + 2 \r
\n" ); document.write( "\n" ); document.write( "a. Put this equation in standard form for a parabola.
\n" ); document.write( "x=-1/4 y2+y+2
\n" ); document.write( "complete the square:
\n" ); document.write( "x=-1/4(y2-4y+4)+2+1
\n" ); document.write( "x=-1/4(y-2)^2+3
\n" ); document.write( "This is an equation of a parabola that opens leftwards.
\n" ); document.write( "Its standard form: y=-A(y-k)^2+h, (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "b. What direction does it open in? Left
\n" ); document.write( "c. What is the coordinate of the vertex? (3,2)
\n" ); document.write( "d. Sketch the graph of the parabola. Sorry, I don't have the means to graph it for you, but you should be able to graph it yourself using coordinates of the vertex and the y-intercepts found as follows:
\n" ); document.write( "set x=0
\n" ); document.write( "0=-1/4(y-2)^2+3
\n" ); document.write( "-1/4(y-2)^2=-3
\n" ); document.write( "(y-2)^2=12
\n" ); document.write( "y-2=±√12=±3.4641
\n" ); document.write( "y=2±3.4641
\n" ); document.write( "y=-1.4641
\n" ); document.write( "and
\n" ); document.write( "y=5.4641
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\n" ); document.write( "e. Find one point on your graph, and test it on the original equation.
\n" ); document.write( "I will leave this one for you to do.
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