document.write( "Question 630454: Please help me solve this problem.
\n" ); document.write( "Peter is Y years old. His brother David is 2 years younger. In 9 years the total of their ages will be 2 times the total of their ages now. \n" ); document.write( "

Algebra.Com's Answer #396918 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+y+\"$ = Peter's age now
\n" ); document.write( " $\"+y+-+2+\"$ = His brother David's age now
\n" ); document.write( " $\"+y+%2B+9+\"$ = Peter's age in 9 years
\n" ); document.write( " $\"+y+-+2+%2B+9+\"$ = David's age in 9 yeats
\n" ); document.write( "------------
\n" ); document.write( "given:
\n" ); document.write( " $\"+y+%2B+9+%2B+y+-+2+%2B+9+=+2%2A%28+y+%2B+y+-+2+%29+\"$
\n" ); document.write( " $\"+2y+%2B+16+=+2%2A%28+2y+-+2+%29+\"$
\n" ); document.write( " $\"+2y+%2B+16+=+4y+-+4+\"$
\n" ); document.write( " $\"+2y+=+20+\"$
\n" ); document.write( " $\"+y+=+10+\"$
\n" ); document.write( " $\"+y+-+2+=+8+\"$
\n" ); document.write( "Peter is 10 now and
\n" ); document.write( "David is 8 now \n" ); document.write( "

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