document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630372>Question 630372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> cos 36 degrees = .8090 how do I find out sin 54 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396883 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3759)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The key here is to recognize that 36 + 54 = 90. Or 54 = 90 -36.<BR>\n" );
document.write( "So we've been given that cos(36) = 0.8090. And we're looking for sin(54) (or sin(90 - 36).<br><BR>\n" );
document.write( "One of the properties/identities you should know is:<BR>\n" );
document.write( "cos(x) = sin(90-x).<BR>\n" );
document.write( "So if cos(36) = 0.8090 then sin(90-26) is also 0.8090. </SPAN>\n" );
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