document.write( "Question 630333: I have been asked to test a piece of material that is 1/2\" thick by 1\" wide in a continuos length. The instruction states that specimen shall be 1/2\" in thickness and 4 square inches in area. I would assume that the length needed should be 4\". I have been told that it is 2\" because both the top and bottom surfaces count. Is this true? \n" ); document.write( "
Algebra.Com's Answer #396861 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I have been asked to test a piece of material that is 1/2\" thick by 1\" wide in a continuos length. The instruction states that specimen shall be 1/2\" in thickness and 4 square inches in area. I would assume that the length needed should be 4\". I have been told that it is 2\" because both the top and bottom surfaces count. Is this true? \n" ); document.write( "-------- \n" ); document.write( "top + bottom area = 2(1\" * 2\") = 4 in^2 \n" ); document.write( "---- \n" ); document.write( "Side area = 2((1/2)\" * 1\") + 2((1/2)\" * 2\") = 2[(1/2)+1) = 3 in^2 \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |