document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630272>Question 630272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> perpendicular to the line 7x+y=-55; contains the point (-7,-7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396799 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite the line as y=-7x-55. So the slope of the line is -7. Therefore the slope of a perpendicular line is 1/7. For the equation of the perpendicular line thru the point (-7,-7) we have y+7=(1/7)(x+7). </SPAN>\n" );
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