document.write( "Question 630234: a man walking with a speed of 5 km/hr reached his target 5 minutes late. if he walks at a speed of 6 km/hr, he reached on time. find the distance of his target from his house? \n" ); document.write( "
Algebra.Com's Answer #396785 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "a man walking with a speed of 5 km/hr reached his target 5 minutes late.
\n" ); document.write( "if he walks at a speed of 6 km/hr, he reached on time\"highlight%28x%29\"
\n" ); document.write( "Note: D = rt (distance the same both ways)
\n" ); document.write( "Question states*** takes 5min\"%281%2F12%29hr\" longer at 5kmph
\n" ); document.write( " \"6kmph%2At+=+5kmph%28t%2B+1%2F12%29\"
\n" ); document.write( " t = 5/12 hr and D = \"6mph%2A%285%2F12%29hr+=+%285%2F2%29mi\"\r
\n" ); document.write( "\n" ); document.write( "and...
\n" ); document.write( " \"5kmph%2A%286%2F12%29hr+=+%285%2F2%29mi\" \n" ); document.write( "
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