document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630230>Question 630230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd numbers whose sum is 5 more than twice the next <BR>\n" );
document.write( "    consecutive number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396783 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2n+1, 2n+3, 2n+5, 2n+7\r<BR>\n" );
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document.write( "2n+1 + 2n + 3 + 2n+5 = 2(2n+7) + 5\r<BR>\n" );
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document.write( "6n + 9 = 4n + 14 + 5\r<BR>\n" );
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document.write( "2n = 10\r<BR>\n" );
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document.write( "n = 5\r<BR>\n" );
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document.write( "plugging back in to get the consecutive odd numbers:\r<BR>\n" );
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document.write( "11, 13, 15, 17\r<BR>\n" );
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document.write( "11 + 13 + 15 = 39 = 2(17) + 5 = 34 + 5 = 39\r<BR>\n" );
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document.write( "39 = 39\r<BR>\n" );
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