document.write( "Question 58025: 44. One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
\n" ); document.write( "A) 5
\n" ); document.write( "B) 7
\n" ); document.write( "C) 17
\n" ); document.write( "D) 34
\n" ); document.write( "I really appreciate your help!!!! \n" ); document.write( "
Algebra.Com's Answer #39678 by tutorcecilia(2152)\"\" \"About 
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\n" ); document.write( "x= One number
\n" ); document.write( "x+12 = the other number is 12 more than another
\n" ); document.write( "x+2(x+12) = The sum (addition) of the smaller number and twice the larger
\n" ); document.write( "Total= is 39
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\n" ); document.write( "Putting it all together:
\n" ); document.write( "x+ 2(x+12)=39
\n" ); document.write( "x+2x+24=39
\n" ); document.write( "3x+24=39
\n" ); document.write( "3x+24-24=39-24
\n" ); document.write( "3x=15
\n" ); document.write( "x=5
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\n" ); document.write( "The smaller number = 5
\n" ); document.write( "The larger number = (x+12)=(5+12)=17
\n" ); document.write( "Plugging the values back into the original equation:
\n" ); document.write( "x+ 2(x+12)=39
\n" ); document.write( "(5)+ 2((5)+12)=39
\n" ); document.write( "(5)+ 2((5)+12)=39
\n" ); document.write( "5+2(17)=39
\n" ); document.write( "5+34=39
\n" ); document.write( "39=39 [checks out]\r
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