document.write( "Question 630214: 1 + 4/7- 3/4\r
\n" ); document.write( "\n" ); document.write( "I am not sure where the order of operations start? Do I start with the fractoions and find a common denominator and then what do I do with the 1?\r
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Algebra.Com's Answer #396773 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your expression is:
\n" ); document.write( "1 + 4/7- 3/4
\n" ); document.write( "steps:
\n" ); document.write( "1. divide 4 by 7.
\n" ); document.write( "2. add it to 1.
\n" ); document.write( "3. divide 3 by 4.
\n" ); document.write( "4. subtract it from the result in step 2.\r
\n" ); document.write( "\n" ); document.write( "the results from your calculator will show:
\n" ); document.write( "1. 4/7 = .5714295871
\n" ); document.write( "2. .5714295871 + 1 = 1.5714295871
\n" ); document.write( "3. 3/4 = .75
\n" ); document.write( "4. 1.5714295871 - .75 = .821428571\r
\n" ); document.write( "\n" ); document.write( "if you want to deal with fractions rather than decimals, you would need to get everything under a common denominator before performing any operations.\r
\n" ); document.write( "\n" ); document.write( "your expression is:
\n" ); document.write( "1 + 4/7- 3/4
\n" ); document.write( "lowest common denominator appears to be 28, so makes everything equivalent to a fraction with a denominator of 28.
\n" ); document.write( "you get:
\n" ); document.write( "28/28 + 16/28 - 21/28
\n" ); document.write( "since the denominators are common, you can add the numerators together under the common denominator to get:
\n" ); document.write( "(28 + 16 - 21) / 28
\n" ); document.write( "perform the operation within each set of parenthese first to get:
\n" ); document.write( "23/28
\n" ); document.write( "decimal equivalent of this is equal to .821428571.\r
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\n" ); document.write( "\n" ); document.write( "that's the same answer you got before.
\n" ); document.write( "here's a reference on order of arithmetic operations.
\n" ); document.write( "http://math.about.com/library/weekly/aa040502a.htm
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