document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630095>Question 630095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if log(2)3 = a and log(2)7 = b, express the following in terms of a & b.\r<BR>\n" );
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document.write( "log(8)72 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396724 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if log(2)3 = a and log(2)7 = b, <BR>\n" );
document.write( "express the following in terms of a & b. <BR>\n" );
document.write( "log(8)72 = log2(72)/log(2)8 = [log2(8)+log2(9)]/log2(8) <BR>\n" );
document.write( "----<BR>\n" );
document.write( "= 1 + [log2(9)/log2(8)]<BR>\n" );
document.write( "==<BR>\n" );
document.write( "= 1 + [2log2(3)/3]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= 1 + (2/3)a<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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