document.write( "Question 629914: two function f and g are defined by :\r
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document.write( "f(x)=2x+1
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document.write( "g(x)=x^2\r
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document.write( "verify that (fog)^-1 = g^-1 o f^-1 \n" );
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Algebra.Com's Answer #396654 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! Inverses of of functions are found by swapping the x's and y's. To perform this swap, I like to temporarily replace the function notation with a \"y\": \n" ); document.write( "f(x) = 2x+1 \n" ); document.write( "y = 2x + 1 \n" ); document.write( "Swap the x's and y's: \n" ); document.write( "x = 2y + 1 <=== This is the inverse, but not in a desired form \n" ); document.write( "Solve for y: \n" ); document.write( "x - 1 = 2y \n" ); document.write( "Divide by 2 (or multiply by 1/2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Doing the same for g(x): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "+ \n" ); document.write( "Note: Because of the +, the inverse of g is not a function (i.e. some, in fact all, x's have more than one y value). And since this inverse is not a function, I do not believe it is proper to use function notation, g^-1 on it. \n" ); document.write( "For the compositions it helps if we have a good understanding of what the function's definition is telling you. For example \n" ); document.write( "f(x) = 2x+1 \n" ); document.write( "The left side tells us that the input to the function, between the parentheses after the function name, is being called \"x\". \"x\" is just a placeholder. It is just being used as a name for the input to the function. We could use any letter here to name the input. f(q) = 2q+1 is the exact same function as f(x)!! \n" ); document.write( "The right side tells us what function f does with its input. It multiplies the input, x, by 2 and then adds 1. Since \"x\" is just a place holder, function f will take any input, multiply it by 2 and then add 1: \n" ); document.write( "f(7) = 2(7) + 1 \n" ); document.write( "f(1002.4) = 2(1002.4) + 1 \n" ); document.write( "f(12x-3) = 2(12x-3) + 1 \n" ); document.write( "etc. \n" ); document.write( "(fog)(x) is just another way to write f(g(x)). In f's parentheses we have \"g(x)\". So \"g(x)\" is the input to f. And what does f do to its input? Answer: it multiplies by 2 and then adds 1!: \n" ); document.write( "f(g(x)) = 2(g(x)) + 1 \n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "Now we find the inverse of fog: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "+ \n" ); document.write( "Again, we get an inverse that is not a function. \n" ); document.write( "For g^-1 o f^-1, we use the two inverses we found back at the start and feed the inverse of f into the inverse of g as its input: From the inverse of g, + \n" ); document.write( "+ \n" ); document.write( "which matches the inverse of fog! \n" ); document.write( " |