document.write( "Question 629996: Hello I am working on even, odd, or neither functions. I have been doing great on most of them until I hit one that i really do not get.
\n" ); document.write( "My question: is log(x^2/y) even, odd, or neither?
\n" ); document.write( "i know that when log(x/y) it is the same as logx-logy. I tried separating it like that, and then changing the sign. so my problem was like :
\n" ); document.write( "log(x^2/y)= logx^2-logy
\n" ); document.write( "f(x)=logx^2-logy
\n" ); document.write( "f(-x)=-logx^2+logy
\n" ); document.write( "this function is odd.\r
\n" ); document.write( "\n" ); document.write( "I do not know if i am doing it right, I would just want to know how to do it. Thanks
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Algebra.Com's Answer #396625 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
A function is \"even\" if f(-x) = f(x) for all x's in the domain.
\n" ); document.write( "A function is \"odd\" if f(-x) = -f(x) for all x's in the domain.
\n" ); document.write( "A function is \"neither\" if it is not even or odd.

\n" ); document.write( "Logarithms are perhaps the ultimate \"neither\". If log(x) exists, log(-x) does not even exist since arguments of logs can only be positive!
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