document.write( "Question 629915: For 2 consecutive years cheese prices rose by 10%. At the beginning of the first year 1 kg of cheese cost $5.00. At the end of the second year how many grams of cheese could be bought for $10.00? \n" ); document.write( "

Algebra.Com's Answer #396615 by josmiceli(19441) $\"\"$ $\"About$

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At the end of the 1st year 1 kg of cheese
\n" ); document.write( "will cost $\"+5+%2B+.1%2A5+=+5.5+\"$ or $5.50
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\n" ); document.write( "At the end of the 2nd year, 1 kg costs
\n" ); document.write( " $\"+5.5+%2B+.1%2A5.5+=+6.05+\"$ , or $6.05
\n" ); document.write( "The price is $\"+6.05+%2F+1000+=+.00605+\"$ dollars/gram
\n" ); document.write( "In units:
\n" ); document.write( "( grams ) = ( dollars ) / ( dollars / gram )
\n" ); document.write( " $\"+10+%2F+.00605+=+1652.89+\"$ grams of cheese
\n" ); document.write( "can be bought for $10
\n" ); document.write( "------------------
\n" ); document.write( "The answer looks close because if the price hadn't
\n" ); document.write( "gone up, you could get 2000 grams for $10 \n" ); document.write( "

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