document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629949>Question 629949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am very confused do you think someone could double check my work?<BR>\n" );
document.write( "b.	Suppose that an object is 200 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.) <BR>\n" );
document.write( "The equation: C=wr^2<BR>\n" );
document.write( "200*3963^2<BR>\n" );
document.write( "C=3141073800<BR>\n" );
document.write( "c.	Use the value of C you found in the previous question to determine how much the object would weigh in \r<BR>\n" );
document.write( "\n" );
document.write( "	i.Dead Sea, Jordon, Israel (1,388 feet below sea level, the lowest level in the world)<BR>\n" );
document.write( "3963-1388/5280=0.2629 <BR>\n" );
document.write( "3141073800*3962.737=12447249366990.6 feet<BR>\n" );
document.write( "The formula needed: Cr^-2=w<BR>\n" );
document.write( "w=3141073800*3962.737^-2=200.0266<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396613 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   <PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><font face = \"Tohoma\" size = 3 color = \"indigo\"><b> <BR>\n" );
document.write( "Hi,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+wr%5E2+=+200%2A%283963%29%5E2+ ALIGN=MIDDLE  ALT=\"C+=+wr%5E2+=+200%2A%283963%29%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >= 3,141,073,800  Yes!  or 3,141,073,800/(3963)^2 ~ 200<BR>\n" );
document.write( " w when r = 1,388   <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w+=+C%2Fr%5E2 ALIGN=MIDDLE  ALT=\"w+=+C%2Fr%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3141073800%2F%281388%29%5E2=+3141073800%2F1926544 ALIGN=MIDDLE  ALT=\"3141073800%2F%281388%29%5E2=+3141073800%2F1926544\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1630.4189    Note:  w will be more as r is less<BR>\n" );
document.write( "   Estimating Answer:   ~ 3x10^9/2x10^6 = 1.5x10^3 = 1500<BR>\n" );
document.write( "Re: TY  Note: 1500 was just an approxiamation, which is something recommended<BR>\n" );
document.write( "when dealing with large numbers...to get a 'ballpark' fiqure to compare with.<BR>\n" );
document.write( "1630.4189 is the Actual weight.  Round as directed.  rounded to the nearest whole number would be 1630.<BR>\n" );
document.write( "Yes, the idea is 'weightlessness' is something reserved for being  a very... long ways <u>above</u> the earth's surface.  </SPAN>\n" );
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