document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629861>Question 629861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a field is 500 feet. Its width (shorter side) is 32 feet less than half its length (longer side). What is its width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396581 by </B><A HREF=/tutors/aboutme.mpl?userid=Taino><B>Taino(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Taino><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Data given: \r<BR>\n" );
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document.write( "Perimeter of a rectangular field = 500 ft.\r<BR>\n" );
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document.write( "Length of the field = L<BR>\n" );
document.write( "Width (W) of the field = 1/2*L - 32\r<BR>\n" );
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document.write( "Perimeter equation for a rectangle: P = 2*L + 2*W\r<BR>\n" );
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document.write( "500 = 2L + 2*(1/2*L -32)<BR>\n" );
document.write( "500 = 2L + L - 64 <BR>\n" );
document.write( "500 = 3L - 64<BR>\n" );
document.write( "500 + 64 = 3L\r<BR>\n" );
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document.write( "564 = 3L ----->  L = 564/3 -----> L = 188 Ft.\r<BR>\n" );
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document.write( "Therefore, W = 1/2*L - 32 = 1/2*(188) - 32 = 94 - 32 = 62 Ft.<BR>\n" );
document.write( "           W = 62 Ft.\r<BR>\n" );
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document.write( "The width of the field is 62 feet. </SPAN>\n" );
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