document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629851>Question 629851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can I ask the following step by step procedures in this Problem so that I could understand the solution.thanks<BR>\n" );
document.write( "PROBLEM:\n" );
document.write( "     The sum of twice the 1st, four times the 2nd plus the 3rd of the three consecutive even integers is equal to 96. find the integers<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396561 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The three consecutive even integers are 2n,2n+2 and 2n+4. We have that\n" );
document.write( "2*(2n)+4*(2n+2)+2n+4=96\n" );
document.write( "Do multiplications\n" );
document.write( "4n+8n+8+2n+4=96\n" );
document.write( "Variables on the left and numbers on the right.\n" );
document.write( "4n+8n+2n=96-8-4\n" );
document.write( "14n=84\n" );
document.write( "Divide both sides by 14\n" );
document.write( "14n/14=84/1r\n" );
document.write( "n=6\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );