document.write( "Question 629851: Can I ask the following step by step procedures in this Problem so that I could understand the solution.thanks
\n" ); document.write( "PROBLEM:\n" ); document.write( " The sum of twice the 1st, four times the 2nd plus the 3rd of the three consecutive even integers is equal to 96. find the integers
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Algebra.Com's Answer #396559 by unlockmath(1688)\"\" \"About 
You can put this solution on YOUR website!
Hello,
\n" ); document.write( "Setting up these problems is sometimes the toughest.
\n" ); document.write( "Let x be the first even integer (x+2) and (x+4) be the next ones.
\n" ); document.write( "Now we can write the equation as:
\n" ); document.write( "2x+4(x+2)+(x+4)=96
\n" ); document.write( "Combine like terms:
\n" ); document.write( "7x+12=96
\n" ); document.write( "Subtract 10 and divide by 7 to get:
\n" ); document.write( "x=12
\n" ); document.write( "So therefore the even numbers are:
\n" ); document.write( "12,14,16
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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