document.write( "Question 629851: Can I ask the following step by step procedures in this Problem so that I could understand the solution.thanks
\n" );
document.write( "PROBLEM:\n" );
document.write( " The sum of twice the 1st, four times the 2nd plus the 3rd of the three consecutive even integers is equal to 96. find the integers
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #396559 by unlockmath(1688) You can put this solution on YOUR website! Hello, \n" ); document.write( "Setting up these problems is sometimes the toughest. \n" ); document.write( "Let x be the first even integer (x+2) and (x+4) be the next ones. \n" ); document.write( "Now we can write the equation as: \n" ); document.write( "2x+4(x+2)+(x+4)=96 \n" ); document.write( "Combine like terms: \n" ); document.write( "7x+12=96 \n" ); document.write( "Subtract 10 and divide by 7 to get: \n" ); document.write( "x=12 \n" ); document.write( "So therefore the even numbers are: \n" ); document.write( "12,14,16 \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |