document.write( "Question 629642: Stopping at the apple stand for his weekly purchase of fifty cents’ worth of apples, Professor Digit was pleased to find that he was given five more apples than usual.\r
\n" ); document.write( "\n" ); document.write( "“Hmm!” he said. “I see the price has gone down ten cents per dozen.”\r
\n" ); document.write( "\n" ); document.write( "What was the new price per dozen?\r
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\n" ); document.write( "\n" ); document.write( "This will be a quadratic equation. I can solve it if you can figure out what the equation is. Thank you!! \n" ); document.write( "

Algebra.Com's Answer #396546 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
Another of many ways to solve it:
\n" ); document.write( "Let the old price per dozen (in cents) be $\"p\"$ .
\n" ); document.write( "The number of apples he used to get was $\"n=%2850%2Fp%29%2A12=600%2Fp\"$ , so
\n" ); document.write( " $\"n=600%2Fp\"$ --> $\"np=600\"$
\n" ); document.write( "This time he got 5 more apples, or $\"n%2B5\"$ apples,
\n" ); document.write( "at a price of $\"p-10\"$ cents per dozen, so
\n" ); document.write( " $\"%28%28n%2B5%29%2F12%29%2A%28p-10%29=50\"$ --> $\"%28n%2B5%29%28+p-10%29=50%2A12=600\"$ --> $\"np-10n%2B5p-50=600\"$ --> $\"600-10n%2B5p-50=600\"$ --> $\"-10n%2B5p-50=0\"$
\n" ); document.write( "Here I would divide both side of the equal sign by 5
\n" ); document.write( " $\"-10n%2B5p-50=0\"$ --> $\"-2n%2Bp-10=0\"$ --> $\"-2np%2Bp%5E2-10p=0\"$ --> $\"-2%2A600%2Bp%5E2%2A10p=0\"$ --> $\"highlight%28+p%5E2-10p-1200=0%29\"$
\n" ); document.write( "I would solve that equation by factoring; discard the negative value for $\"p\"$ ,
\n" ); document.write( "and then I would subtract 10 to find the new price per dozen (in cents). \n" ); document.write( "

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