document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57973>Question 57973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 108. Area of a sail. A triangular sail has as area of x^2+5x+6 square meters and the height of x+3 meters find the length of the sails base.  Area = x^2 +5x+6m^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39654 by </B><A HREF=/tutors/aboutme.mpl?userid=jaya_rohith1@yahoo.com><B>jaya_rohith1@yahoo.com(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jaya_rohith1@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of the sail = x^2+5x+6<BR>\n" );
document.write( "Height           = x+3<BR>\n" );
document.write( "Area of the triangle = 1/2 * base * height<BR>\n" );
document.write( "x^2+5x+6 = 1/2 * base * x+3<BR>\n" );
document.write( "Base = 2(x^2+5x+6)/(x+3)<BR>\n" );
document.write( "     = 2(x+2)(x+3)/(x+3)<BR>\n" );
document.write( "     = 2(x+2) </SPAN>\n" );
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