document.write( "Question 629491: 1/x-1/y
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\n" ); document.write( "1/x+1/y Simplify.\r
\n" ); document.write( "\n" ); document.write( "When I first attempted this problem, I multiplied the numerators of the fractions that make up the numerator (1-1)of the overall fractions with the denominators of the denominator of the fraction (x + y). I did the same with the numerators of the denominator and the denominator of the numerator, to get x+y/x-y. Seeing that this was one of the answer choices, I assumed it to be correct. I may have been a bit hasty in this, as my answer turned out to be wrong.\r
\n" ); document.write( "\n" ); document.write( "Please walk me through this problem so I can solve similar ones on my upcoming math placement exam! Thank you so much.
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Algebra.Com's Answer #396515 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2Fx-1%2Fy%29%2F%281%2Fx%2B1%2Fy%29\" = \"%28%28y-x%29%2Fxy%29%2F%28%28y%2Bx%29%2Fxy%29\"
\n" ); document.write( "invert the dividing fraction and multiply, the xy cancels:
\n" ); document.write( "\"%28y-x%29%2F%28xy%29\" * \"%28xy%29%2F%28y%2Bx%29\" = \"%28y-x%29%2F%28y%2Bx%29\"
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