document.write( "Question 629805: Becky and Sam are both taking History and attend independently. Becky attends 83.9% of the time and Sam attends 95.1% of the time.\r
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document.write( "-What is the probability that at least 1 will NOT be in class?
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document.write( " I believe that this is 1-(Probability of both in class). P=1-(.951*.839) or .20211\r
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document.write( "-What is the probability that NEITHER are in class on any given day?
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document.write( "I believe that this would be the complements multiplied: P= (.161*.049) or .007889\r
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document.write( "I think that I have worked these out correctly, but am not entirely sure.
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Algebra.Com's Answer #396507 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yes and yes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |