document.write( "Question 629722: Sammy bought DVDs and CDs. She spent the same amount of money on both. If DVDs cost $16 and CDs cost $12, what is the least she could have spent total? \n" ); document.write( "
Algebra.Com's Answer #396458 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = the number of DVD's she bought
\n" ); document.write( "Let \"+b+\" = the number of CD's she bought
\n" ); document.write( "given:
\n" ); document.write( "\"+16a+=+12b+\" ( she spent the same on each )
\n" ); document.write( "\"+a%2Fb+=+12%2F16+\"
\n" ); document.write( "\"+a%2Fb+=++3%2F4+\"
\n" ); document.write( "3 DVDs and 4 CDs is the least she could have bought
\n" ); document.write( "\"+3%2A16+%2B+4%2A12+=+48+%2B+48+\"
\n" ); document.write( "\"+2%2A48+=+96+\"
\n" ); document.write( "The least she could have spent total was $96
\n" ); document.write( "
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