document.write( "Question 629265: Let tan(alpha) , tan(beta) be the roots of equation x^2-px+q=0, then find cos2(alpha + beta). \n" ); document.write( "
Algebra.Com's Answer #396454 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! There may be be a much easier way to do this. But since you haven't gotten a response in over a day, I'd thought I'd give it a try. \n" ); document.write( "To save on typing I'm going to use A and B instead of alpha and beta. \n" ); document.write( "Using the Quadratic Formula on \n" ); document.write( " \n" ); document.write( "Simplifying... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which is short for \n" ); document.write( " \n" ); document.write( "It doesn't matter which one we say is tan(A) and which one is tan(B). So I'll make the first root tan(A) and the second one tan(B). \n" ); document.write( "Next we use the formula for \n" ); document.write( " \n" ); document.write( "Simplifying... (Note: to multiply the two numerators in the denominator, I am going to use the \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "From this we are going to find an expression for sin(A+B). tan is opposite/adjacent. So draw a right triangle, pick one of the acute angles and make the opposite side \"p\" and the adjacent side \"1+q\". Then use the Pythagorean Theorem to find the hypotenuse. You should get \n" ); document.write( " \n" ); document.write( "Next we will use the \n" ); document.write( " \n" ); document.write( "Replacing the sin(A+B) with the expression we found earlier: \n" ); document.write( " \n" ); document.write( "Simplifying: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |