document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629703>Question 629703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square has a diagonal that is 34yd long. What is the area of the square?\r<BR>\n" );
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document.write( "If necessary, round your answer to the nearest whole number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396440 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well, i guess we can do a reverse a^2+b^2=c^2 on this one since we already know what the hypotenuse is, sooooo, lets go ahead and multiply 34 by itsself\r<BR>\n" );
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document.write( "34^2 is 1156.  with that we can divide that in half to get our a^2+b^2  which will give us 578 + 578   lets get the square roots of those to get our lengths shall we  it gives us roughly 24.04   soooooooo, our area will be length times width, which will be 24.04 times 24.04.  which gives us a rounded up number of 578 sq/yds </SPAN>\n" );
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