document.write( "Question 629643: if the roots of x^2-ax+b=0 are real & differ by a quantity which is less than c(c>0),prove that b lies between (1/4)(a^2-c^2)& (1/4)a^2 \n" ); document.write( "
Algebra.Com's Answer #396439 by jsmallt9(3758)\"\" \"About 
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Using the Quadratic Formula on your equation we get:
\n" ); document.write( "\"x+=+%28-%28-a%29+%2B-+sqrt%28%28-a%29%5E2-4%281%29%28b%29%29%29%2F2%281%29\"
\n" ); document.write( "which simplifies as follows:
\n" ); document.write( "\"x+=+%28-%28-a%29+%2B-+sqrt%28a%5E2-4%281%29%28b%29%29%29%2F2%281%29\"
\n" ); document.write( "\"x+=+%28-%28-a%29+%2B-+sqrt%28a%5E2-4b%29%29%2F2%281%29\"
\n" ); document.write( "\"x+=+%28a+%2B-+sqrt%28a%5E2-4b%29%29%2F2\"
\n" ); document.write( "which is short for:
\n" ); document.write( "\"x+=+%28a+%2B+sqrt%28a%5E2-4b%29%29%2F2\" or \"x+=+%28a+-+sqrt%28a%5E2-4b%29%29%2F2\"

\n" ); document.write( "The difference of these is:
\n" ); document.write( "\"%28a+%2B+sqrt%28a%5E2-4b%29%29%2F2+-+%28a+-+sqrt%28a%5E2-4b%29%29%2F2\"
\n" ); document.write( "\"%282sqrt%28a%5E2-4b%29%29%2F2\"
\n" ); document.write( "\"sqrt%28a%5E2-4b%29\"

\n" ); document.write( "We are told that this difference is less than c, and as is true of any square root, it is not negative. So
\n" ); document.write( "\"sqrt%28a%5E2-4b%29+%3C+c\" and \"sqrt%28a%5E2-4b%29+%3E=+0\"
\n" ); document.write( "Squaring both sides of both we get:
\n" ); document.write( "\"a%5E2-4b+%3C+c%5E2\" and \"a%5E2-4b+%3E=+0\"
\n" ); document.write( "Now we solve both for b:
\n" ); document.write( "\"a%5E2-c%5E2+%3C+4b\" and \"a%5E2+%3E=+4b\"
\n" ); document.write( "\"%281%2F4%29%28a%5E2-c%5E2%29+%3C+b\" and \"%281%2F4%29a%5E2+%3E=+b\"

\n" ); document.write( "P.S. To me, \"between p and q\" means \"between p and q but not equal to p or q\". But I don't think there is any way to eliminate the \"or equal to\" part of \"%281%2F4%29a%5E2+%3E=+b\". So the largest possible b would be equal to \"%281%2F4%29a%5E2\" not between that and \"%281%2F4%29%28a%5E2-c%5E2%29\".
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