document.write( "Question 629682: The base of a triangle is twelve more than twice its height. If the area of a triangle is 46 square centimeters, find its base and height. \n" ); document.write( "
Algebra.Com's Answer #396434 by lwsshak3(11628)\"\" \"About 
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The base of a triangle is twelve more than twice its height. If the area of a triangle is 46 square centimeters, find its base and height.
\n" ); document.write( "let x=height of triangle
\n" ); document.write( "2x+12=base of triangle
\n" ); document.write( "Area of triangle=1/2*base*height
\n" ); document.write( "..
\n" ); document.write( "46=1/2*(2x+12)*x
\n" ); document.write( "92=2x^2+12x
\n" ); document.write( "2x^2+12x-92=0
\n" ); document.write( "x^2+6x-46=0
\n" ); document.write( "Solve by following quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "a=1, b=6, c=-46
\n" ); document.write( "ans:
\n" ); document.write( "x≈4.42
\n" ); document.write( "2x+12≈20.83
\n" ); document.write( "height of triangle≈4.42 cm
\n" ); document.write( "base of triangle≈20.83 cm \n" ); document.write( "
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