document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57941>Question 57941</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534490247/algebrahomeworkh>Elementary and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> To Whomever can assist, Thank You!\r<BR>\n" );
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document.write( "If the total surface area of a right circular cylinder is 104PIE square meters and a radius of the base is 4 meters long, find the height of the cylinder. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39630 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CIRCUMFERANCE OF THE BASE=2PIR THUS<BR>\n" );
document.write( "C=2PI4<BR>\n" );
document.write( "C=2*PI*4<BR>\n" );
document.write( "C=8PI <BR>\n" );
document.write( "THE AREA OF THE TOP IS A=PIR^2<BR>\n" );
document.write( "A=PI*4^2<BR>\n" );
document.write( "A=PI*16 OR A=16PI AND THERE ARE 2 CIRCULAR AREAS (TOP & BOTTOM) THUS<BR>\n" );
document.write( "2*PI*16=32PI <BR>\n" );
document.write( "THE CYLINDER SIDE AREA IS 8P1*HEIGHT<BR>\n" );
document.write( "THUS THE TOTAL SURFACE AREA BEING 104PI=32PI+8PI*H<BR>\n" );
document.write( "104PI-32PI=8PI*H<BR>\n" );
document.write( "72PI=8PI*H<BR>\n" );
document.write( "H=72PI/8PI<BR>\n" );
document.write( "H=9 METERS<BR>\n" );
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