document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629508>Question 629508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit number is 10 . if the number formed by reversing the digit is less than the original number by 36.find the number .\r<BR>\n" );
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document.write( "WITH BEST REGARDS . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396299 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = units digit<BR>\n" );
document.write( "    y = ten's digit<BR>\n" );
document.write( "The value of the number is x + 10y<BR>\n" );
document.write( "The new value after reversing the digits is 10x + y\r<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 10 and<BR>\n" );
document.write( "10x + y = x + 10y - 36 or 9x - 9y = -36  or  x - y = -4<BR>\n" );
document.write( "Add the 2 equations, the result is 2x = 6<BR>\n" );
document.write( "so x = 3 and y = 7<BR>\n" );
document.write( "The original number is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%2873%29 ALIGN=MIDDLE  ALT=\"highlight%2873%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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