document.write( "Question 629485: a group of friends bought a gift for $60 when 3 more people chipped in, each share decreased by $1.00. How many people contributed in the end and much did they pay? \n" ); document.write( "
Algebra.Com's Answer #396292 by rajagopalan(174)\"\" \"About 
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scene 1..
\n" ); document.write( "Let the Number of friends=x
\n" ); document.write( "Let the initial contribution =y
\n" ); document.write( "we get 1 equation x*y=60
\n" ); document.write( "we can write y=60/x
\n" ); document.write( "..
\n" ); document.write( "scene 2..
\n" ); document.write( "number of fiends=x+3
\n" ); document.write( "fresh contribution =y-1
\n" ); document.write( "we get equation2 (x+3)*(y-1)=60
\n" ); document.write( "expand eqn 2 & equate it to 1
\n" ); document.write( "xy=xy+3y-3-x
\n" ); document.write( "0=3y-x-3...eqn3
\n" ); document.write( "substitute y=60/x in eqn 3
\n" ); document.write( "0=3(60/x)-x-3
\n" ); document.write( "{(180-x^2-3x)/x}=0
\n" ); document.write( "x^2+3x-180=0
\n" ); document.write( "x^2+15x-12x-180=0
\n" ); document.write( "x(x+15)-12(x+15)=0
\n" ); document.write( "(x+15)(x-12)=0
\n" ); document.write( "x=-15 or 12
\n" ); document.write( "ignore negative value
\n" ); document.write( "we get number of initial friends=12
\n" ); document.write( "additional friends=3
\n" ); document.write( "Total friends=12+3=15
\n" ); document.write( "each contributed 60/15=4 dollars
\n" ); document.write( "cheers\r
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