document.write( "Question 629427: The following table lists the probability distribution of the number of sandwiches made during lunch hour at a deli based on data from the past 50 days.
\n" ); document.write( " | Sandwiches Made | Probability |
\n" ); document.write( " | 43 | .04 |
\n" ); document.write( " | 45 | .06 |
\n" ); document.write( " | 47 | .12 |
\n" ); document.write( " | 48 | .10 |
\n" ); document.write( " | 49 | .20 |
\n" ); document.write( " | 50 | .22 |
\n" ); document.write( " | 51 | .18 |
\n" ); document.write( " | 52 | .04 |
\n" ); document.write( " | 53 | .04 |
\n" ); document.write( " |—————————————————+—————————————|
\n" ); document.write( " How many times during the last 50 days were less than 49 sandwiches made?
\n" ); document.write( " a. 10
\n" ); document.write( " b. 12
\n" ); document.write( " c. 16
\n" ); document.write( " d. 26 \n" ); document.write( "
Algebra.Com's Answer #396260 by 55305(86)\"\" \"About 
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First we should add up the percents for the days where the # of sandwiches made is less than 49. So 0.04+ 0.06+ 0.12+ 0.10= 0.32. Then we multiply 0.32 and 50 together to get 16.
\n" ); document.write( "So the answer is c.16 days. \n" ); document.write( "
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