document.write( "Question 629354: Dear tutor I was wondering on how to find the quotient of my problem but by only using positive exponents.\r
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\n" ); document.write( "\n" ); document.write( "18a^-20/8a^9\r
\n" ); document.write( "\n" ); document.write( "I am very unsure on what steps to take to solve it. \r
\n" ); document.write( "\n" ); document.write( "Also I need help on this:\r
\n" ); document.write( "\n" ); document.write( "(w^3)(y^13)/(w^11)(y^6)\r
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Algebra.Com's Answer #396219 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Reduce \"18%2F8\" to get \"9%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "and then subtract the exponents:\r
\n" ); document.write( "\n" ); document.write( "-20 - 9 = -29\r
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\n" ); document.write( "\n" ); document.write( "So \"%2818a%5E%28-20%29%29%2F%288a%5E9%29+=+%289a%5E%28-29%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "Then flip the base to make the exponent positive \"+%289%29%2F%284a%5E%2829%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%2818a%5E%28-20%29%29%2F%288a%5E9%29+=+%289%29%2F%284a%5E%2829%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract the corresponding exponents over 'w' to get 3 - 11 = -8\r
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\n" ); document.write( "\n" ); document.write( "Subtract the corresponding exponents over 'y' to get 13 - 6 = 7\r
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\n" ); document.write( "\n" ); document.write( "So \"%28%28w%5E3%29%28y%5E13%29%29%2F%28%28w%5E11%29%28y%5E6%29%29+=+w%5E%28-8%29y%5E7\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, flip the base with the negative exponent to get \"w%5E%28-8%29y%5E7=%28y%5E7%29%2F%28w%5E8%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%28%28w%5E3%29%28y%5E13%29%29%2F%28%28w%5E11%29%28y%5E6%29%29+=+%28y%5E7%29%2F%28w%5E8%29\"\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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