document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629276>Question 629276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the diameter of a pizza is doubled what happens to its total area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396200 by </B><A HREF=/tutors/aboutme.mpl?userid=55305><B>55305(86)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=55305><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the diameter is doubled, then the radius is also doubled. So we have the formula of finding the area of a circle:<BR>\n" );
document.write( "A= (pi)*r^2,<BR>\n" );
document.write( "where r is the radius and A is the area of the circle.<BR>\n" );
document.write( "So if we multiply r times 2 and plug that into the formula instead of r, we get A= (pi)*(2*r)^2, and since (2*r)^2= 4*r^2 we can replace 4*r^2 with (2*r)^2.<BR>\n" );
document.write( "So now the formula looks like this: <BR>\n" );
document.write( "A= (pi)*4*r^2, and if you compare that to the original formula of finding the area of a circle, you can see that an extra 4 is being multiplied, meaning that the area is 4 times as larger.\r<BR>\n" );
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document.write( "So if the diameter of the pizza is doubled, then total area quadruples(gets 4 times as larger). </SPAN>\n" );
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