document.write( "Question 629255: Hello, \r
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document.write( "How to solve x + y =10
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document.write( "Where y is 4 years older than x. \n" );
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Algebra.Com's Answer #396136 by darknez25(6)![]() ![]() ![]() You can put this solution on YOUR website! y is 4 years older than x. \n" ); document.write( "i.e \n" ); document.write( " y=x+4 --- let this be equation no.(1) \n" ); document.write( " \n" ); document.write( " x+y=10 \n" ); document.write( " \n" ); document.write( " putting the value of y fro, the equation (1) \n" ); document.write( " \n" ); document.write( " x+x+4=10 \n" ); document.write( " 2x=10-4 \n" ); document.write( " 2x=6 \n" ); document.write( " x=3 ---(2)\r \n" ); document.write( "\n" ); document.write( " now putting the value of x in eq. (1)\r \n" ); document.write( "\n" ); document.write( " y=3+4 \n" ); document.write( " y=7\r \n" ); document.write( "\n" ); document.write( " There for the value of x=3 and of y=7 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |