document.write( "Question 629209: If you fold a square paper vertically, the new rectangle has a perimeter of 39 inches. What is the area of the original square? What is the perimeter of the original square? What is the area of the resulting rectangle? \n" ); document.write( "
Algebra.Com's Answer #396097 by richwmiller(17219)\"\" \"About 
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2x+2y=39
\n" ); document.write( "x=y/2
\n" ); document.write( "2*y/2+2y=39
\n" ); document.write( "3y=39
\n" ); document.write( "y=13
\n" ); document.write( "13+26=39
\n" ); document.write( "x=6.5
\n" ); document.write( "y=13
\n" ); document.write( "13^2=169 sq inches =area of original square
\n" ); document.write( "4*13=52 inches =perimeter of original square.
\n" ); document.write( "6.5*13=84.5 sq in area of rectangle
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