document.write( "Question 629209: If you fold a square paper vertically, the new rectangle has a perimeter of 39 inches. What is the area of the original square? What is the perimeter of the original square? What is the area of the resulting rectangle? \n" ); document.write( "
Algebra.Com's Answer #396097 by richwmiller(17219) You can put this solution on YOUR website! 2x+2y=39 \n" ); document.write( "x=y/2 \n" ); document.write( "2*y/2+2y=39 \n" ); document.write( "3y=39 \n" ); document.write( "y=13 \n" ); document.write( "13+26=39 \n" ); document.write( "x=6.5 \n" ); document.write( "y=13 \n" ); document.write( "13^2=169 sq inches =area of original square \n" ); document.write( "4*13=52 inches =perimeter of original square. \n" ); document.write( "6.5*13=84.5 sq in area of rectangle \n" ); document.write( " |