document.write( "Question 629167: ONE NUMBER EXCEEDS ANOTHER BY 5. TWO TIMES THE SMALLER NUMBER DIMINISHED BY THE LARGER NUMBER EQUALS 9. FIND THE TWO NUMBERS? \n" ); document.write( "
Algebra.Com's Answer #396077 by 303795(602)\"\" \"About 
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Let the smaller number be x. This means that the second number is 5 larger than x.
\n" ); document.write( "Number 1 = x
\n" ); document.write( "Number 2 = x + 5
\n" ); document.write( "2 times the smaller number is 2x.
\n" ); document.write( "Using this information we then get the equation
\n" ); document.write( "2x - (x + 5) = 9
\n" ); document.write( "Remove the bracket by multiplying the contents by minus
\n" ); document.write( "2x - x - 5 = 9
\n" ); document.write( "x - 5 = 9 Add 5 to each side to get
\n" ); document.write( "x = 9 + 5 = 14
\n" ); document.write( "So the second number must be 19.
\n" ); document.write( "Check 2 x 14 - 19 = 9 \n" ); document.write( "
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