document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629126>Question 629126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two friends who live 4km apart, arrange to meet. They both leave home at the same time, one walking at 6km/h while the other runs at an average speed of 14 km/h. After how many minutes will the two friends meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396051 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two friends are getting closer to each other at a combined speed of (6 + 14) km/h = 20 km/h.\r<BR>\n" );
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document.write( "Time = Distance/speed<BR>\n" );
document.write( "The time taken to travel 4 km at a speed of 20 km/h is<BR>\n" );
document.write( "4/20 =0.2 hours<BR>\n" );
document.write( "0.2 hour is 0.2 x 60 = 12 minutes<BR>\n" );
document.write( "i.e. they meet after 12 minutes </SPAN>\n" );
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