document.write( "Question 629147: information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f
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document.write( "Degree 3; zeros: 5,-4i \n" );
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Algebra.Com's Answer #396050 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! The degree of a polynomials tells you how many zeros there are. So f(x) has three zeros. You were only given 2 zeros so one is missing. \n" ); document.write( "If a polynomial with real coefficients has a complex zero, then the complex conjugate of that zero will also be a zero. A complex number in standard form is: \n" ); document.write( "a + bi \n" ); document.write( "The complex conjugate of this is: \n" ); document.write( "a - bi or a + (-bi) \n" ); document.write( "f(x) has a complex zero: -4i. So the complex conjugate of -4i will be our missing zero. -4i in standard form is: \n" ); document.write( "0 + (-4i) \n" ); document.write( "Its complex conjugate will be: \n" ); document.write( "0 - (-4i) or 0 + 4i or just 4i \n" ); document.write( "So the only zero that you were not given was 4i. \n" ); document.write( " |