document.write( "Question 629145: Three years ago a man was eight times as old as his son.In two years he will be four and a half time as old as the son.Find the present age. \n" ); document.write( "
Algebra.Com's Answer #396044 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Three years ago a man was eight times as old as his son age \"highlight%28x%29\"
\n" ); document.write( "In two years he will be four and a half time as old as the son
\n" ); document.write( "Question ALSO states*** Using 5 years from 3 years ago...
\n" ); document.write( " 8x + 5 = 9/2(x+5) |Multiplying thru by 2 so as all denominators = 1
\n" ); document.write( " 16x +10 = 9x + 45
\n" ); document.write( " 7x = 35
\n" ); document.write( " x = 5, son's age 3 years ago, father was 40
\n" ); document.write( "Presently the son is 8 and the father is 43\r
\n" ); document.write( "\n" ); document.write( "and...2 years from mow, checking our Answer
\n" ); document.write( " \"+45+=+%289%2F2%2910\"
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