document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=629098>Question 629098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7x-8y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #396032 by </B><A HREF=/tutors/aboutme.mpl?userid=lenny460><B>lenny460(1073)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lenny460><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lenny460><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=396032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Plot the following graph:\r<BR>\n" );
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document.write( "7x - 8y = 3\r<BR>\n" );
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document.write( "Subtract 7x from each side of the equation\r<BR>\n" );
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document.write( "7x - 8y - 7x = 3 - 7x\r<BR>\n" );
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document.write( "Combine like terms:\r<BR>\n" );
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document.write( "7x - 7x = 0\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "-8y = 3 - 7x or\r<BR>\n" );
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document.write( "-8y = -7x + 3\r<BR>\n" );
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document.write( "Divide each item by -1\r<BR>\n" );
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document.write( "-8y/-1 = -7x/-1 + 3/-1\r<BR>\n" );
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document.write( "We now have:\r<BR>\n" );
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document.write( "8y = 7x - 3\r<BR>\n" );
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document.write( "From the above we get the following coordinates:\r<BR>\n" );
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document.write( "(2,11)\r<BR>\n" );
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document.write( "(1,4)\r<BR>\n" );
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document.write( "(0,-3)\r<BR>\n" );
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document.write( "(-1,-10)\r<BR>\n" );
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document.write( "The Slope (m) formula: (y2 - y1)/(x2 - x1)\r<BR>\n" );
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document.write( "= (-3 - 4)/(0 - 1)\r<BR>\n" );
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document.write( "= -3 - 4 = -7\r<BR>\n" );
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document.write( "= 0 - 1 = -1\r<BR>\n" );
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document.write( "-7/-1 = 7\r<BR>\n" );
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document.write( "The Slope (m) = 7\r<BR>\n" );
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document.write( "y-intercept = -3\r<BR>\n" );
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document.write( "y = mx + b\r<BR>\n" );
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document.write( "y = 7x - 3\r<BR>\n" );
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document.write( "obuong3@aol.com </SPAN>\n" );
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