document.write( "Question 629109: How do i find the exact values of x for which 3(2x-1)^2+2(2x-1)-8=0?
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Algebra.Com's Answer #396029 by lwsshak3(11628)\"\" \"About 
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How do i find the exact values of x for which
\n" ); document.write( "3(2x-1)^2+2(2x-1)-8=0?
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\n" ); document.write( "let u=(2x-1)
\n" ); document.write( "u^2=(2x-1)^2
\n" ); document.write( "..
\n" ); document.write( "3u^2+2u-8=0
\n" ); document.write( "(3u-4)(u+2)=0
\n" ); document.write( "u=4/3=2x-1
\n" ); document.write( "6x-3=4
\n" ); document.write( "6x=7
\n" ); document.write( "x=7/6
\n" ); document.write( "or
\n" ); document.write( "u=-2=2x-1
\n" ); document.write( "2x=-1
\n" ); document.write( "x=-1/2
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