document.write( "Question 629058: If log(base 5)2 = m , express log 20 in terms of m.
\n" ); document.write( "I tried splitting log 20 into log 2 + log 10 = log 2 + 1
\n" ); document.write( "And played around with log(base 5)2 = log2/log5 = m\r
\n" ); document.write( "\n" ); document.write( "But I can't reach the answer of (2m+1)/(m+1)
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Algebra.Com's Answer #396006 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
If log(base 5)2 = m , express log 20 in terms of m.
\n" ); document.write( "---------
\n" ); document.write( "\"log%285%2C2%29+=+m\"
\n" ); document.write( "----
\n" ); document.write( "If you mean \"log%2810%2C20%29\"
\n" ); document.write( "then,
\n" ); document.write( "\"log%285%2C2%29+=+m\"
\n" ); document.write( "20 = 2*5*2
\n" ); document.write( "log(20) = log(2) + log(5) + log(2) to any base
\n" ); document.write( "\"log%285%2C20%29+=+m+%2B+1+%2B+m+=+2m%2B1\"
\n" ); document.write( "---------
\n" ); document.write( "\"log%285%2C10%29+=+log%282%29+%2B+log%285%29+=+m%2B1\"
\n" ); document.write( "-----
\n" ); document.write( "Use base change:
\n" ); document.write( "\"log%2810%2C20%29+=+log%285%2C20%29%2Flog%285%2C10%29\"
\n" ); document.write( "= (2m+1)/(m+1)
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