document.write( "Question 629058: If log(base 5)2 = m , express log 20 in terms of m.
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document.write( "I tried splitting log 20 into log 2 + log 10 = log 2 + 1
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document.write( "And played around with log(base 5)2 = log2/log5 = m\r
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document.write( "But I can't reach the answer of (2m+1)/(m+1) \n" );
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Algebra.Com's Answer #396006 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If log(base 5)2 = m , express log 20 in terms of m. \n" ); document.write( "--------- \n" ); document.write( " \n" ); document.write( "---- \n" ); document.write( "If you mean \n" ); document.write( "then, \n" ); document.write( " \n" ); document.write( "20 = 2*5*2 \n" ); document.write( "log(20) = log(2) + log(5) + log(2) to any base \n" ); document.write( " \n" ); document.write( "--------- \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "Use base change: \n" ); document.write( " \n" ); document.write( "= (2m+1)/(m+1) \n" ); document.write( " \n" ); document.write( " |