document.write( "Question 629014: An auditor of Health Maintenance Services of Georgia reports 40 percent of policyholders 55 years or older submit a claim during the year. Fifteen policyholders are randomly selected for company records. \r
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document.write( "A. How many of the policy holders would you expect to have filed a claim within the last year?
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document.write( "B. What is the probability that 10 of the selected policyholders submitted a claim last year?
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document.write( "C. What is the probability that 10 or more of the selected policyholders submitted a claim last year?
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document.write( "D. What is the probability that more than 10 of the selected policyholders submitted a claim last year?
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Algebra.Com's Answer #395974 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An auditor of Health Maintenance Services of Georgia reports 40 percent of policyholders 55 years or older submit a claim during the year. Fifteen policyholders are randomly selected for company records. \n" ); document.write( "A. How many of the policy holders would you expect to have filed a claim within the last year? \n" ); document.write( "---- \n" ); document.write( "expected value = np = 15*0.4 = 6 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "B. What is the probability that 10 of the selected policyholders submitted a claim last year? \n" ); document.write( "P(x = 10) = 15C10*0.4^10*0.6^5 = binompdf(15,0.4,10) = 0.0245 \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "C. What is the probability that 10 or more of the selected policyholders submitted a claim last year? \n" ); document.write( "P(10<= x <= 15) = 1 - binomcdf(15,0.4,9) = 0.0338 \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "D. What is the probability that more than 10 of the selected policyholders submitted a claim last year? \n" ); document.write( "P(11<= x <=15) = 1 - binomcdf(15,0.4,10) = 0.0093 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================== \n" ); document.write( " \n" ); document.write( " |